OH → WV · about 242 miles
Cleveland to Martinsburg train schedule
Amtrak runs 7 direct trains a week from Cleveland to Martinsburg. The fastest takes 9 hours 12 minutes; the first train leaves at 1:24 AM and the last at 1:54 AM.
Timetable data from · Schedule last changed
- Trains a week
- 7
- Fastest trip
- 9h 12m
- First train
- 1:24 AM
- Last train
- 1:54 AM
Timetable
Every train leaves from Cleveland and arrives at Martinsburg Amtrak Station. Times are local to each stop. Timetables published by tds.ai, refreshed October 15, 2026. Schedules change, so check times when you book.
| Departs | Arrives | Duration | Days | Rail company |
|---|---|---|---|---|
| 1:24 AM New | 11:06 AM | 9h 42m | Mon | Amtrak Full timetable |
| 1:54 AM | 11:06 AM | 9h 12m | Daily | Amtrak Full timetable |
Route map
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Where to board in Cleveland Where you get off in Martinsburg The route of the busiest trip
Where to catch the train in Cleveland
Where the train stops in Martinsburg
- Martinsburg Amtrak Station Map of Martinsburg Amtrak Station (Google Maps)
Return trip: Martinsburg to Cleveland
Questions
How long is the train from Cleveland to Martinsburg?
The fastest direct train takes 9 hours 12 minutes; the typical trip is 9 hours 12 minutes.
What time is the first train from Cleveland to Martinsburg?
The earliest departure is at 1:24 AM (Mon) and the last at 1:54 AM (Daily).
Which rail companies go from Cleveland to Martinsburg?
Amtrak runs direct trains on this route.
Where do I catch the train in Cleveland?
Trains to Martinsburg leave from Cleveland Amtrak station.